How to cast/convert pointer to reference in C++
How can I pass a pointer (Object *ob) to a function which prototype is void foo(Object &) ?
Solution 1:
Call it like this:
foo(*ob);
Note that there is no casting going on here, as suggested in your question title. All we have done is de-referenced the pointer to the object which we then pass to the function.
Solution 2:
foo(*ob);
You don't need to cast it because it's the same Object type, you just need to dereference it.