Using ORDER BY and GROUP BY together

My table looks like this (and I'm using MySQL):

m_id | v_id | timestamp
------------------------
6    |   1  | 1333635317
34   |   1  | 1333635323
34   |   1  | 1333635336
6    |   1  | 1333635343
6    |   1  | 1333635349

My target is to take each m_id one time, and order by the highest timestamp.

The result should be:

m_id | v_id | timestamp
------------------------
6    |   1  | 1333635349
34   |   1  | 1333635336

And i wrote this query:

SELECT * FROM table GROUP BY m_id ORDER BY timestamp DESC

But, the results are:

m_id | v_id | timestamp
------------------------
34   |   1  | 1333635323
6    |   1  | 1333635317

I think it causes because it first does GROUP_BY and then ORDER the results.

Any ideas? Thank you.


One way to do this that correctly uses group by:

select l.* 
from table l
inner join (
  select 
    m_id, max(timestamp) as latest 
  from table 
  group by m_id
) r
  on l.timestamp = r.latest and l.m_id = r.m_id
order by timestamp desc

How this works:

  • selects the latest timestamp for each distinct m_id in the subquery
  • only selects rows from table that match a row from the subquery (this operation -- where a join is performed, but no columns are selected from the second table, it's just used as a filter -- is known as a "semijoin" in case you were curious)
  • orders the rows

If you really don't care about which timestamp you'll get and your v_id is always the same for a given m_i you can do the following:

select m_id, v_id, max(timestamp) from table
group by m_id, v_id
order by max(timestamp) desc

Now, if the v_id changes for a given m_id then you should do the following

select t1.* from table t1
left join table t2 on t1.m_id = t2.m_id and t1.timestamp < t2.timestamp
where t2.timestamp is null
order by t1.timestamp desc

Here is the simplest solution

select m_id,v_id,max(timestamp) from table group by m_id;

Group by m_id but get max of timestamp for each m_id.


You can try this

 SELECT tbl.* FROM (SELECT * FROM table ORDER BY timestamp DESC) as tbl
 GROUP BY tbl.m_id